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Question 1:
View the Exhibit and examine the structure of the EMPLOYEES and JOB_HISTORY tables. (Choose all that apply.)
Examine this query which must select the employee IDs of all the employees who have held the job SA_MAN at any time during their employment.
SELECT EMPLOYEE_ID
FROM EMPLOYEES
WHERE JOB_ID = \’SA_MAN\’
SELECT EMPLOYEE_ID
FROM JOB_HISTORY
WHERE JOB_ID = \’SA_MAN\’;
Choose two correct SET operators which would cause the query to return the desired result.
A. UNION
B. MINUS
C. INTERSECT
D. UNION ALL
Correct Answer: AD
Question 2:
View the exhibit and examine the structures of the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES NameNull?Type
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(10,2)
COMMISSIONNUMBER(6,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
DEPARTMENTS
NameNull?Type
DEPARTMENT_IDNOT NULLNUMBER(4) DEPARTMENT_NAMENOT NULLVARCHAR2(30)
MANAGER_IDNUMBER(6)
LOCATION_IDNUMBER(4)
You want to update EMPLOYEES table as follows:
You issue the following command:
SQL> UPDATE employees
SET department_id =
(SELECT department_id
FROM departments
WHERE location_id = 2100),
(salary, commission) =
(SELECT 1.1*AVG(salary), 1.5*AVG(commission)
FROM employees, departments
WHERE departments.location_id IN(2900, 2700, 2100))
WHERE department_id IN
(SELECT department_id
FROM departments
WHERE location_id = 2900
OR location_id = 2700;
What is outcome?
A. It generates an error because multiple columns (SALARY, COMMISSION) cannot be specified together in an UPDATE statement.
B. It generates an error because a subquery cannot have a join condition in a UPDATE statement.
C. It executes successfully and gives the desired update
D. It executes successfully but does not give the desired update
Correct Answer: D
Question 3:
Examine the structure of the ORDERS table: (Choose the best answer.)
You want to find the total value of all the orders for each year and issue this command:
SQL> SELECT TO_CHAR(order_date,\’rr\’), SUM(order_total) FROM orders
GROUP BY TO_CHAR(order_date, \’yyyy\’);
Which statement is true regarding the result?
A. It executes successfully but does not give the correct output.
B. It executes successfully but gives the correct output.
C. It returns an error because the TO_CHAR function is not valid.
D. It return an error because the datatype conversion in the SELECT list does not match the data type conversion in the GROUP BY clause.
Correct Answer: D
Question 4:
Evaluate the following SQL statements that are issued in the given order:
CREATE TABLE emp
(emp_no NUMBER(2) CONSTRAINT emp_emp_no_pk PRIMARY KEY,
ename VARCHAR2(15),
salary NUMBER (8,2),
mgr_no NUMBER(2) CONSTRAINT emp_mgr_fk REFERENCES emp(emp_no));
ALTER TABLE emp
DISABLE CONSTRAINT emp_emp_no_pk CASCADE;
ALTER TABLE emp
ENABLE CONSTRAINT emp_emp_no_pk;
What would be the status of the foreign key EMP_MGR_PK?
A. It would remain disabled and can be enabled only by dropping the foreign key constraint and recreating it.
B. It would remain disabled and has to be enabled manually using the ALTER TABLE command.
C. It would be automatically enabled and immediate.
D. It would be automatically enabled and deferred.
Correct Answer: B
Question 5:
You execute the following commands:
SQL > DEFINE hiredate = \’01-APR-2011\’
SQL >SELECT employee_id, first_name, salary
FROM employees
WHERE hire_date > \’andhiredate\’
AND manager_id >andmgr_id;
For which substitution variables are you prompted for the input?
A. none, because no input required
B. both the substitution variables \’\’hiredate\’ and \’mgr_id\’.
C. only hiredate\’
D. only \’mgr_id\’
Correct Answer: D
1Z0-071 Study Guide1Z0-071 Exam Questions1Z0-071 Braindumps
Question 6:
View the Exhibit and examine the data in the employees table.
You want to generate a report showing the total compensation paid to each employee to date. You issue the following query:
What is the outcome?
A. It executes successfully but does not give the correct output.
B. It generates an error because the concatenation operator can be used to combine only two items.
C. It generates an error because the usage of the round function in the expression is not valid
D. It generates an error because the alias is not valid.
E. It executes successfully and gives the correct output.
Correct Answer: A
Question 7:
Which two statements are true about Data Manipulation Language (DML) statements?
A. An INSERT INTO…VALUES.. statement can add multiple rows per execution to a table.
B. An UPDATE… SET… statement can modify multiple rows based on multiple conditions on a table.
C. A DELETE FROM….. statement can remove rows based on only a single condition on a table.
D. An INSERT INTO… VALUES….. statement can add a single row based on multiple conditions on a table.
E. A DELETE FROM….. statement can remove multiple rows based on multiple conditions on a table.
F. An UPDATE….SET…. statement can modify multiple rows based on only a single condition on a table.
Correct Answer: BE
http://www.techonthenet.com/sql/and_or.php
Question 8:
Which two statements are true regarding the EXISTS operator used in the correlated subqueries? (Choose two.)
A. The outer query stops evaluating the result set of the inner query when the first value is found.
B. It is used to test whether the values retrieved by the inner query exist in the result of the outer query.
C. It is used to test whether the values retrieved by the outer query exist in the result set of the inner query.
D. The outer query continues evaluating the result set of the inner query until all the values in the result set are processed.
Correct Answer: AC
http://www.techonthenet.com/oracle/exists.php
Question 9:
View the exhibit and examine the ORDERS table. ORDERS Name Null? Type ORDER ID NOT NULL NUMBER(4)
ORDATE DATE
DATE
CUSTOMER ID
NUMBER(3)
ORDER TOTAL
NUMBER(7,2)
The ORDERS table contains data and all orders have been assigned a customer ID. Which statement would add a NOT NULL constraint to the CUSTOMER_ID column?
A. ALTER TABLE ordersMODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
B. ALTER TABLE ordersADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
C. ALTER TABLE ordersMODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
D. ALTER TABLE ordersADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
Correct Answer: C
Question 10:
Which three statements are true about the ALTER TABLE….DROP COLUMN…. command?
A. A column can be dropped only if it does not contain any data.
B. A column can be dropped only if another column exists in the table.
C. A dropped column can be rolled back.
D. The column in a composite PRIMARY KEY with the CASCADE option can be dropped.
E. A parent key column in the table cannot be dropped.
Correct Answer: BDE
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